Question

If $\log 2=0.3010$ and $\log 3=0.4771$, then the value of $\log 6$ will be

• A. $0.7781$
• B. $0.6991$
• C. $0.8066$
• D. $0.6981$

Answer 1

The correct option is A $0.7781$

Using the Logarithmic property,

$\log ab=\log a+\log b$

$\log 6=\log (2\times 3)$

$=\log 2+\log 3$

$=0.3010+0.4771$

$=0.7781$