Question

If $\log 2=0.3010$ and $\log 3=0.4771$, then the value of $\log 1.2$ is $0.792$.

If true then write 1 and if false then write 0.

Answer 1

$x=\log 1.2$
$\therefore x=\log 12-\log 10$
$\therefore x=\log (2^2\cdot 3)-1$
$\therefore x=\log 2^2+\log 3-1$ (Using $\log (a\cdot b)=\log a)+\log b$
$\therefore x=2\log 2+\log 3-1$ (Using $\log a^b=b\log a$)
$\therefore x=2\times 0.3010+0.4771-1=0.0791$