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Question

If logab+logba=log(a+b), then

A
a+b=0
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B
a+b=1
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C
ab=0
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D
ab=1
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Solution

The correct option is B a+b=1
logab+logba=log(a+b)
log(ab×ba)=log(a+b)
log1=log(a+b)
a+b=1

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