Question

If $\log \left(6\right)=\log x+\log 2+\log 3$ then $x=$

Answer 1

$\log 6=\log x+\log 2+\log 3$

$\Rightarrow \log 6=\log x\times 2\times 3$ since $\log ab=\log a+\log b$

$\Rightarrow \log 6=\log 6x$

$\Rightarrow {10}^{6x}={10}^6$

Since bases are same, we can equate the bases

$\Rightarrow 6x=6$

$\therefore x=1$