If log (m+n)=log m+ log n ,show that n=m/(m-1).

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Solution

log(m+n)= logm+ logn

log(m+n) = log(mn). [ loga+logb =log ab]

log on both sides gets cancel
then,

m+n = mn
=> m= mn -n
=> m = n(m-1)
=> n = m/m-1 [proved]

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