If $log (m + n) = log m + log n$ , then what is the relation between $n$ and $m$ ?

m . n = 1

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m = - n

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\frac{m}{(m - 1)} = n

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\frac{m}{n} = 1

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Solution

The correct option is B $\frac{m}{(m - 1)} = n$
Given, $log (m + n) = log m + log n$
$\Rightarrow log (m + n) = log (m n)$
$\Rightarrow m + n = m n$
Removing $log$ , we get
$\Rightarrow m = n (m - 1)$
$\Rightarrow n = \frac{m}{(m - 1)}$

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