If logx(7x−10)=2, then find the value(s) of x.
logx(7x−10)=2
⇒x2=7x−10 ...... [∵alogax=x]
⇒x2−7x+10=0
⇒x2−5x−2x−10=0
⇒(x−5)(x−2)=0
Hence, x=5orx=2
If x=1(2−√3), then find the value of (x3−2x2−7x+5).