If m and 2 m 2 are the roots of x 2- px - q -0- then q -4 q 2-6 pq - -A- 0 B- p 3C- q2 D- 2 p 3

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Quadratic Equations

If m and 2 m ...

Question

If $m$ and $2 m^{2}$ are the roots of $x^{2} - p x + q = 0$ , then $q + 4 q^{2} + 6 p q =$ :

q^{2}

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p^{3}

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0

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2 p^{3}

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Solution

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Similar questions

f (x) = x^{2} - p x + q

x = 2 k^{2}

q + 4 (q^{2}) + 6 p q =

s e c α, c o s e c α

x^{2} - p x + q = 0

p^{2} - 2 q - q^{2} = 0

x^{2} - x s i n α + c o s α = 0

p^{2} = \frac{1 - q^{2}}{1 + q^{2}}

x^{2} - p x + q = 0

1,

p^{2} + 4 q^{2}

If a, b be the roots $x^{2} + p x - q$ =0 and g,d be the roots of $x^{2} + p x + r$ =0 , q+r =1 then $\frac{(a - g) (a - d)}{(b - g) (b - d)}$ is ……

a, b

x^{2} + p x - q = 0

c, d

x^{2} + p x + r = 0

(a - c) (a - d)

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