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Question

If m and n are order and degree of the equation (d2ydx2)5+4.(d2ydx2)3(d3ydx3)+(d3ydx3)=x21, then

A
m=3,n=3
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B
m=3,n=2
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C
m=3,n=5
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D
m=3,n=1
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Solution

The correct option is D m=3,n=2
The given differential equation can be rewritten as
(d2ydx2)5d3ydx3+4(d2ydx2)3+(d3ydx3)2
=(x21)d3ydx3 order (m) =3
and degree (n)=2

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