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Question

If m arithmetic means are inserted between 1 and 31 so that the ratio of the 7th and (m−1)th means is 5:9, then the value of m is

A
9
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B
11
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C
13
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D
14
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Solution

The correct option is D 14
m arithmetic mean are inserted between 1 and 31
7thmean(m1)thmean=591+7d1+(m1)d=59=>9+63d=5+5(m1)d4=5md68d1+(m1)d=31mdd=305×2=>73d=146d=2m=14

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