If M g - M - g - e - - - H -90 eV - M g - M 2- g -2 e - - - H -260 eVWhat is electron gain enthalpy of M 2- g -A- 260 eVB- 170 eVC- -260 eVD- -170 eV

The correct option is D 170 eVM^2+(g) +e^ → M^+(g) Δ H=90 260= 170 eV So, electron gain enthalpy of M^2+= 170 eV ...

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Question

If $M (g) \to M^{+} (g) + e^{-}; Δ H = 90 e V$ , $M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 260 e V$ .
What is electron gain enthalpy of $M^{2 +} (g)$ ?

260 eV

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170 eV

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-260 eV

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-170 eV

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Similar questions

M (g) \to M^{+} (g) + e^{-}; Δ H = 100 e V M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 250 e V

I E =

Δ H_{g e} =

M (g) \to M^{+} (g) + e^{-}, Δ H = 100 e V

M (g) \to M^{2 +} (g) + 2 e^{-}, Δ H = 250 e V

M (g) \to M^{+} (g) + e^{-}; Δ H = 100 e V M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 250 e V

I E =

Δ H_{g e} =

M (g) \to M^{+} (g) + e^{-}, Δ H = 100 e V, M (g) \to M^{2 +} (g) + 2 e^{-}, Δ H = 250 e V

M (g) \to M^{+} (g) + e^{-}; Δ H = 100 e V

M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 250 e V

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