Mg - M- g - e- - H - 100 eV Mg - M2- g - 2e- - H - 250 eVwhich is incorrect statement-

The correct option is B I_2 of M(g) is 250 eV #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; # ...

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Ionisation Energy

Mg → M+ g + ...

Question

$M (g) \to M^{+} (g) + e^{-}, Δ H = 100 e V$
$M (g) \to M^{2 +} (g) + 2 e^{-}, Δ H = 250 e V$
which is incorrect statement?

I_{1}

M (g)

is 100 eV

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I_{1}

M^{+} (g)

is 150 eV

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I_{2}

M (g)

is 250 eV

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I_{2}

M (g)

is 150 eV

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Solution

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Similar questions

M (g) \to M^{+} (g) + e^{-}, Δ H = 100 e V, M (g) \to M^{2 +} (g) + 2 e^{-}, Δ H = 250 e V

M (g) \to M^{+} (g) + e^{-}; Δ H = 100 e V

M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 250 e V

M (g) \to M^{+} (g) + e -; Δ H = 100 e V

M (g) \to M^{2 +} (g) + e -; Δ H = 250 e V

M (g) \to M^{+} (g) + e^{-}; Δ H = 90 e V

M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 260 e V

M^{2 +} (g)

M (g) \to M^{+} (g) + e^{-}; Δ H = 100 e V M (g) \to M^{2 +} (g) + 2 e^{-}; Δ H = 250 e V

I E =

Δ H_{g e} =

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