If m is the mass- Q is the charge and B is the magnetic induction- mBQ has the same dimensions as -

The correct option is D Time F=BQV F=ma ma=BQV mBQ=Va=LT^ 1LT^ 2=T ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Analysis of Force Equation

If m is the...

Question

If $m$ is the mass, $Q$ is the charge and $B$ is the magnetic induction, $\frac{m}{B Q}$ has the same dimensions as :

Frequency

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Time

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Velocity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Acceleration

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Time
$F = B Q V$
$F = m a$
$m a = B Q V$
$\frac{m}{B Q} = \frac{V}{a} = \frac{L T^{- 1}}{L T^{- 2}} = T$

Suggest Corrections

Similar questions

Q. Which of the following do not have the same dimensions as the other three?

Given that:

l =

length,

m =

mass,

k =

force constant,

I =

momet of inertia,

B =

magnetic induction,

P_{m} =

magnetic dipole moment,

R =

radius and

g =

acceleration due to gravity

Q. A particle of mass m and charge q is projected into a region that has a perpendicular magnetic field B. Find the angle of deviation (figure) of the particle as it comes out of the magnetic field if the width d of the region is very slightly smaller than
(a)

\frac{m v}{q B}

(b)

\frac{m v}{2 q B}

(c)

\frac{2 m v}{q B}

Q. The dimension of magnetic induction in

M, L, T

and

C

(Coloumb) is given as:

Q. A particle of mass m and charge

q

is fired perpendicular to a uniform magnetic field of induction

B

. While the particle moves in a circular path in the field, its angular velocity is

Find the dimensions of

(a) electric dipole moment p and

(b) magnetic dipole moment M.

The defining equations are p = q,d and M = IA;

where d is distance, A is area, q is charge and I is current.

Join BYJU'S Learning Program

If m is the mass, Q is the charge and B is the magnetic induction, mBQ has the same dimensions as :

The correct option is D TimeF=BQVF=mama=BQVmBQ=Va=LT−1LT−2=T

If $m$ is the mass, $Q$ is the charge and $B$ is the magnetic induction, $\frac{m}{B Q}$ has the same dimensions as :

The correct option is D Time
$F = B Q V$
$F = m a$
$m a = B Q V$
$\frac{m}{B Q} = \frac{V}{a} = \frac{L T^{- 1}}{L T^{- 2}} = T$