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Bricks Logarithm

If m = log ...

Question

If $m = log 20$ and $n = log 25$ , then the value of $x$ , so that $2 log (x - 4) = 2 m - n$ is equal to

6

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Solution

The correct option is B $8$
$m = log 20 n = log 25 2 log (x - 4) = 2 log 20 - log 25 log {(x - 4)}^{2} = log 20^{2} - log 25 = log (\frac{20^{2}}{25}) = log \frac{4 \times 5 \times 4 \times 5}{5 \times 5} log {(x - 4)}^{2} = log 4^{2} x - 4 = 4 . . . removing log x = 8$

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Similar questions

If $m = l o g 20$ and $n = l o g 25$ , find the value of x, so that : $2 l o g (x - 4) = 2 m - n$ .

m = log 20

n = log 25

2 log (x - 4) = 2 m - n

x

p = log 20

q = log 25

x

2 log (x + 1) = 2 p - q

m = \frac{1}{3 - \sqrt{8}}

n = \frac{1}{3 + \sqrt{8}}

m^{2}

17 + 6 \sqrt{n}

n

\frac{2^{m + 1} \times 3^{2 m - n} \times 5^{m + n} \times 6^{n}}{6^{m} \times 10^{n + 2} \times 15^{m}}

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