If m, n are the positive integers (n > 1) such that $m^{n} = 121$ then value of ${(m - 1)}^{n + 1}$ is

12321

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1000

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Solution

The correct option is C 1000
We know that $11^{2} = 121$ So $m = 11$ and $n = 2$ so,
$(m - 1)^{n + 1} = (11 - 1)^{2 + 1} = 10^{3} = 1000$
Answer (C) 1000

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