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Question

If x3x-y2x+z3y-ω=3247, find x, y, z, ω.

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Solution

Since all the corresponding elements of a matrix are equal,
x3x-y2x+z3y-w=3247x=3 ...13x-y=2 ...2Putting the value of x in eq. 2, we get33-y=29-y=2-y=-7 y=72x+z=4 ...3Putting the value of x in eq. 3, we get23+z=46+z=4z=4-6z=-23y-w=7 ...4Putting the value of y in eq. 4, we get37-w=721-w=721-7=ww=14 x=3 , y=7, z=-2 and w=14

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