If A- 0 2- 3 -4 - kA- 0 3a- 2b 24 - - then arrange the values of k-a-b- in ascending order

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Scalar Multiplication of a Matrix

If A=[ 0 2;...

Question

If $A = {\begin{matrix} 0 & 2 3 & - 4 \end{matrix}}, k A = {\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}}$ , then arrange the values of $k, a, b,$ in ascending order

k, a, b

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b, a, k

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a, k, b

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b, k, a

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Solution

The correct option is A $b, k, a$
Directly comparing the corresponding terms we get,
$2 k = 3 a$ ,
$3 k = 2 b$ ,
$- 4 k = 24$
we get $k = - 6$ , $b = - 9$ , $a = - 4$
$b < k < a$

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If A={023−4}, kA={03a2b24} , then arrange the values of k,a,b, in ascending order

The correct option is A b,k,aDirectly comparing the corresponding terms we get,2k=3a,3k=2b,−4k=24we get k=−6,b=−9,a=−4b<k<a

If $A = {\begin{matrix} 0 & 2 3 & - 4 \end{matrix}}, k A = {\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}}$ , then arrange the values of $k, a, b,$ in ascending order

The correct option is A $b, k, a$
Directly comparing the corresponding terms we get,
$2 k = 3 a$ ,
$3 k = 2 b$ ,
$- 4 k = 24$
we get $k = - 6$ , $b = - 9$ , $a = - 4$
$b < k < a$