If nA-4-nB-3-nA- B- C-24- then nC-

n(A)=4 n(B)=3 n(A× B× C)=24 n(C)= 24 4× 3 =2 ...

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Ratio a:b:c and Its Simplification

If nA=4,nB=...

Question

If $n (A) = 4, n (B) = 3, n (A \times B \times C) = 24$ , then $n (C) =$

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Solution

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A, B & C,

n (A \cup B \cup C) = n (A) + n (B) + n (C)

- n (A \cap B) - n (B \cap C) - n (C \cap A)

+ n (A \cap B \cap C)

n (A \times B \times C) = 24, t h e n n (C)

n (A \cap B) = 3, n (B \cap C) = 6, n (A \cap C) = 5 a n d n (A \cap B \cap C) = 2

n [A \cup B \cup C] =

\cup

\cup

\cap

\cap

\cap

\cap

\cap

n (A \times B \times C) = 36 f i n d n (C)

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