If nA-6-nB-8 and nA- B-12- then nA- B-

The correct option is A 2 We know that n(A)+n(B)=n(A∪ B)+n(A∩ B) n(A)=6, n(B)=8 and n(A∪ B)=12 n(A)+n(B) n(A∪ B)=n(A∩ B) n ...

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Addition Theorem of Probability for 2 Events

If nA=6,nB=...

Question

If $n (A) = 6, n (B) = 8$ and $n (A \cup B) = 12$ , then $n (A \cap B) =$

6

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2

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8

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12

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n (A \cup B) = 8, n (A) = 6, n (B) = 4

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n (A \cup B) .

A

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If A and B be any two sets where $n (A - B) = 8$ , $n (A \cup B) = 20$ and $n (A \cap B) = 6$ , then $n (B - A)$ is

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