If NA is the Avogadro’s number, then the number of valence electrons in 4.2g of nitride ions (N3−) is:
A
4.2NA
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B
2.4NA
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C
1.6NA
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D
3.2NA
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Solution
The correct option is B2.4NA Moles of nitride ion ⇒givenmassmolarmass ⇒4.214=0.3NA nitride ions.
The number of valence electrons in an nitride ion =8(5+3due to the charge)
The number of valence electrons in 4.2g of nitride ions⇒8×0.3NA=2.4NA