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Question

If nC4,nC5 and nC6 are in A.P., then the value of n can be

A
14
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B
11
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C
7
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D
8
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Solution

The correct options are
A 14
C 7
2.nC5=nC4+nC62.n!(n5)!5!=n!4!(n4)!+n!(n6)!(6!)On solving(17n)(n4)=30n=7,14

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