CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

If nC4, nC5 and nC6 are in A.P., then n can be :

A
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
14
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B 14
nC4, nC5, nC6 are in A.P.

2× nC5= nC4+ nC6
2×n!5!×(n5)!=n!4!×(n4)!+n!6!×(n6)!

25(n5)=1(n4)(n5)+130

From options, n=14 satisfies the above equation.

flag
Suggest Corrections
thumbs-up
1
BNAT
mid-banner-image