If n is a natural number then n -1-2 n - n - is true whenA- n-1 B- n - 1C- n-2D- n - 2

The correct option is B nbsp;1 Check through option, the condition nbsp;(n+1/2)^n nbsp;≥ n ! is true for n nbsp; nbsp;≥ 1. ...

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If n is a nat...

Question

If n is a natural number then ${(\frac{n + 1}{2})}^{n}$ ≥ n ! is true

when

n > 1

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$n\geq$ 1

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n > 2

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$n \geq 2$

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Similar questions

{(\frac{n + 1}{2})}^{n} \geq n!

{(\frac{n + 1}{2})}^{n} \geq n!

If n is a natural number then ${(\frac{n + 1}{2})}^{n}$ ≥ n ! is true

when

n

\frac{C_{0}}{1 \cdot 2} + \frac{C_{1}}{2 \cdot 3} + \frac{C_{2}}{3 \cdot 4} + \dots

C_{r} =^{n} C_{r}

The value of $(n + 1)^{2} - n^{2}$ is equal to

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