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Question

If n is a positive integer, then (1+i1i)4n+1 =

A
1
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B
-1
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C
i
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D
-i
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Solution

The correct option is C i
Since 1+i1i=(1+i)(1+i)(1i)(1+i)=i
Therefore (1+i1i)4n+1=i4n+1=ii4n=i (i4n=1)

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