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Byju's Answer
Standard VIII
Mathematics
Divisibility by 2
If n is an ...
Question
If
n
is an integer, which of the following must be an even integer?
A
n
+
1
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B
n
+
2
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C
2
n
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D
2
n
+
1
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E
n
2
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Solution
The correct option is
C
2
n
⇒
The number which is multiple of
2
is called an even number.
⇒
It is given that
n
is an integer.
⇒
So,
2
n
will be an even number.
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Similar questions
Q.
If
n
represents an odd integer, which of the following must be even integers?
2
n
,
3
n
,
3
n
+
1
,
3
n
−
5
,
4
n
+
1
Q.
Prove that if
n
be an even integer,
1
|
1
–
|
n
−
1
–
––––
–
+
1
|
3
–
|
n
−
3
–
––––
–
+
1
|
5
–
|
n
−
5
–
––––
–
+
.
.
.
.
+
1
|
n
−
1
–
––––
–
|
1
–
=
2
n
−
1
|
n
–
–
.
Q.
The value of
1
1
!
(
n
−
1
)
!
+
1
3
!
(
n
−
3
)
!
+
…
+
1
(
n
−
1
)
!
(
1
)
!
, where
n
is even positive integer, is
Q.
If n is an integer, is n even?
(1)
n
2
−
1
is an odd integer.
(2)
3
n
+
4
is an even integer.
Q.
Prove that
1
−
2
n
+
2
n
(
2
n
−
1
)
2
!
−
2
n
(
2
n
−
1
)
(
2
n
−
1
)
3
!
+
.
.
.
+
(
−
1
)
n
−
1
2
n
(
n
−
1
)
.
.
.
(
n
+
2
)
(
n
−
1
)
=
(
−
1
)
n
+
1
(
2
n
)
2
(
n
!
)
2
,
where n is a + ive integer.
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