Question

If n ∈ N, then $7^{2n}$ + $2^{3n-3}$.$3^{n-1}$ is always divisible by

• A. 25
• B. 35
• C. 45
• D. None of these

Answer 1

The correct option is A

25

Putting n = 1 in $7^{2n}+2^{3n-3}{.3}^{n-1}$

=50, divisible by 25