If $n$ represents an odd integer, which of the following must be even integers?
$2 n, 3 n, 3 n + 1, 3 n - 5, 4 n + 1$

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Solution

Given $n$ is an odd integer
$2 n$ will be always even
$3 n$ will be always odd
$3 n + 1$ will be always even
$3 n - 5$ will be always even
$4 n + 1$ will be always odd
So the correct answer is $2 n, 3 n + 1, 3 n - 5$

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