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Question

If nC2+ nC3= n+1Cr, then the minimum possible value of r is

A
0
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B
3
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C
2
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D
1
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Solution

The correct option is D 1
Given nC2+ nC3= n+1Cr
We know that,
nCr+ nCr1= n+1Cr
So,
nC2+ nC3= n+1Cr n+1C3= n+1Crr=3 or r+3=n+1r=3,n2
From the given expression we know that,
n3
So, the minimum possible value of r is 1 when n=3.

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