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Question

If nC4 = nC6, find 12Cn.

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Solution

We have,
nC4= nC6
n = 6+4 = 10 [∵ nCx = nCy x = y or, n = x+y]

Now, 12C10= 12C2 [∵ nCr = nCn-r]
12C10 =12C2 = 122×111×10C0 [∵ nCr = nr n-1Cr-1]
12C10 = 66 [∵ nC0 = 1]


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