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Byju's Answer
Standard XII
Mathematics
Algebra of Derivatives
If ω is a c...
Question
If
ω
is a cube root of unity, then
(
2
+
5
ω
+
2
ω
2
)
6
=
(
2
+
2
ω
+
5
ω
2
)
6
=
729
A
True
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B
False
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Solution
The correct option is
A
True
(
2
+
ω
+
5
ω
+
2
ω
2
)
6
⟹
(
2
+
ω
+
2
ω
+
2
ω
2
+
3
ω
)
6
⟹
(
2
∗
0
+
3
ω
)
6
=
3
6
.
w
6
=
729
(
2
+
ω
+
2
ω
+
5
ω
2
)
6
⟹
(
2
+
ω
+
2
ω
+
2
ω
2
+
3
ω
2
)
6
⟹
(
2
∗
0
+
3
ω
6
)
6
=
3
6
.
w
12
=
729
Hence proved.
Suggest Corrections
0
Similar questions
Q.
If
ω
is complex cube root of unity then value of
(
2
+
5
ω
+
2
ω
2
)
6
−
(
2
+
2
ω
+
5
ω
2
)
6
i
s
Q.
If
ω
≠
1
is a cube root of unity, then value of the expression
(
1
+
2
ω
+
2
ω
2
)
10
+
(
2
+
ω
+
2
ω
2
)
10
+
(
2
+
2
ω
+
ω
2
)
10
is equal to
Q.
If
ω
is a non real cube root of unity, then
1
+
2
ω
+
3
ω
2
2
+
3
ω
+
ω
2
+
2
+
3
ω
+
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3
+
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+
2
ω
2
=
Q.
1
,
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,
ω
2
are cube roots of unity then
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+
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−
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+
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+
1
2
+
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=
Q.
If
ω
and
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2
are cube roots of unity, prove that
(
2
−
ω
+
2
ω
2
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(
2
+
2
ω
−
ω
2
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9
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