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Byju's Answer
Standard XII
Mathematics
Convexity
If ω is an ...
Question
If
ω
is an imaginary cube root of unity then
(
1
+
ω
−
ω
2
)
7
equals?
A
128
ω
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B
−
128
ω
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C
−
128
ω
2
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D
None of these
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Solution
The correct option is
C
−
128
ω
2
Q. If
ω
is an imaginary. cube root of unity
then
(
1
+
ω
−
ω
2
)
7
equals?
Sol
n
as we know
1
+
ω
+
ω
2
=
0
&
ω
3
=
1
now,
(
1
+
ω
−
ω
2
)
7
=
(
−
ω
2
−
ω
2
)
7
=
(
−
2
ω
2
)
7
=
(
−
2
)
7
.
ω
14
.
(
1
)
=
−
128.
ω
14
.
ω
3
=
−
128.
ω
17
=
−
128.
(
ω
3
)
5
.
ω
2
(
1
+
ω
−
ω
2
)
7
=
−
128
ω
2
Suggest Corrections
0
Similar questions
Q.
If
ω
is an imaginary cube root of unity, then
(
1
+
ω
−
ω
2
)
7
equals
Q.
If
ω
is an imaginary cube root of unity then
(
1
+
ω
−
ω
2
)
7
equals
Q.
If
ω
is an imaginary cube root of unity, then
(
1
+
ω
−
ω
2
)
2
equals
Q.
If
ω
is non-real cube root of unity then
(
1
+
ω
−
ω
2
)
7
equal
Q.
Let
ω
being cube root of unity. Then the value of
(
1
+
ω
−
ω
2
)
7
is
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