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Question

If ω is an imaginary cube root of unity then (1+ωω2)7 equals?

A
128ω
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B
128ω
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C
128ω2
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D
None of these
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Solution

The correct option is C 128ω2
Q. If ω is an imaginary. cube root of unity
then (1+ωω2)7 equals?
Soln as we know 1+ω+ω2=0 & ω3=1
now, (1+ωω2)7
=(ω2ω2)7
=(2ω2)7
=(2)7.ω14.(1)
=128.ω14.ω3
=128.ω17
=128.(ω3)5.ω2
(1+ωω2)7=128ω2

1178724_1071206_ans_d3dc7683cd3048d5b1e838e85ad9005b.jpg

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