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Question

If ω is an imaginary cube root of unity, then (1+ωω2)7 equals

A
128ω
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B
128ω
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C
128ω2
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D
128ω2
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Solution

The correct option is C 128ω2
1+w+w2=0
1+w=w2
Hence
(1+ww2)7
=(2w2)7
=128.w14
=128.w12.w2
=128.w2
Since w3n=1 where n is a natural number.

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