Question

If one electron has been removed from an atom, it becomes increasingly difficult to remove the second and subsequent electrons from the resulting positively charged ions on account of electrostatic attraction.
The numerical value of energy involved in the given process $K\to K^{-}$ is less than that of which of the following processes?

• A. $K^{-}\to K$
• B. $K\to K^{+}$
• C. Both (a) and (b)
• D. None of these

Answer 1

The correct option is B

$K\to K^{+}$

$K\to K^{-}$ is on exothermic process, i.e., the energy involved has -ve value.
$K^{-}\to K$ is opposite of $K\to K^{-}$
$\therefore$ Numerical value would be the same but sign will be opposite. But $K\to K^{+}$ is I.E. of K.
$\therefore$ It is higher than the above process as it is a having a positive value.