If one factor of 5-8 x-4 x2 is 2 x-1- then the second factor isA- 5-2 xB- 2 x-5C- -5-2 xD- 5-2 x

The correct option is D (5 – 2x) 5+8x 4x^2 has (2x+1) as one factor 5+8x 4x^2/2x+1=(5 2x) ∴ (5 2x) is another factor. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Common Factors

If one factor...

Question

If one factor of $5 + 8 x - 4 x^{2}$ is $(2 x + 1)$ , then the second factor is

(5 + 2x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2x - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(5 – 2x)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

–(5 + 2x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

4 x^{2} + 8 x + 3

(x + 1) (x + 3)

(2 x + 1) (2 x + 3)

(2 x + 2) (2 x + 5)

(2 x - 1) (2 x - 3)

x

P (x) = 6 x^{3} + 18 x^{2} + 27 x + 30

(2 x^{2} + 2 x + 5)

P (x)

If (2x+5) is a factor of 2x^2-5 , find the value of x.

4 x^{2} + 9 y^{2} - 8 x - 36 y + 15 = 0

min (x^{2} - 2 x + y^{2} - 4 y + 5) + max (x^{2} - 2 x + y^{2} - 4 y + 5)

Join BYJU'S Learning Program