Question

If one Faraday was to be $48250$ coulomb instead of $96500$ coulomb, what will be charge of an electron?

Answer 1

1 Faraday=charge of 1 mol of electron

let charge of 1 electron = $x$

then $N_{A}x=48250C$

$x=\frac{48250}{6.23\times {10}^{23}}$

$x=0.774\times {10}^{-19}$C