If one gram of tetrahydrocannabinol is 0.00318 mole then the molecular mass of the compound is:

413 amu

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314 amu

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143 amu

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341 amu

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Solution

The correct option is D 314 amu
Mass of compound in 0.00318 mole = 1 gm
Mass of compound of 1 mole $= \frac{1}{0.00318}$ $=$ 314 amu $=$ molar mass of tetrahydrocannabinol.

Hence, the correct option is $(B)$ .

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If one gram of tetrahydrocannabinol is 0.00318 mole then the molecular mass of the compound is:

The correct option is D 314 amuMass of compound in 0.00318 mole = 1 gmMass of compound of 1 mole =10.00318 = 314 amu =molar mass of tetrahydrocannabinol.Hence, the correct option is (B).

The correct option is D 314 amu
Mass of compound in 0.00318 mole = 1 gm
Mass of compound of 1 mole $= \frac{1}{0.00318}$ $=$ 314 amu $=$ molar mass of tetrahydrocannabinol.

Hence, the correct option is $(B)$ .