If one of the factor of $x^{2} + x - 20$ is $(x + 5)$ , find other factor

(x + 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x - 4)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x - 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(x - 4)$
Since, $x + 5$ is factor of $x^{2} + x - 20$ ,
Therefore,
$x + 5) ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ x^{2} + x - 20$ ( $x - 4$
${x -}^{2} + - 5 x - ------ -$
$- 4 x - 20$
$- + 4 x - + 20 - -------- -$
$0$
Therefore, the other factor is $x - 4$

Suggest Corrections

Similar questions

x^{4} + x^{2} - 20

x^{2} + 5

x^{2} + x - 20

(x + 5)

One factor of $x^{4} + x^{2}$ - 20 is $x^{2}$ +5, the other is

Find the value of 'a', if $x + 2$ is a factor of $4 x^{4} + 2 x^{3} - 3 x^{2} + 8 x + 5 a$ .

Join BYJU'S Learning Program