Question

If one vertex of an equilateral triangle of side a is origin and the other lies on the line $x-\sqrt{3}y=0$ then the coordinates of third vertex are

(more than one answer can be correct)

• A. (0, a)
• B. (0, -a)
• C. $[\frac{\sqrt{3}a}{2},-\frac{a}{2}]$
• D. $[-\frac{\sqrt{3}a}{2},\frac{a}{2}]$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A (0, a)
B (0, -a)
C $[\frac{\sqrt{3}a}{2},-\frac{a}{2}]$
D $[-\frac{\sqrt{3}a}{2},\frac{a}{2}]$