Question

If one vertex of an equilateral triangle of side $a$ lies at the origin and the other lies on the line $x-\sqrt{3}y=0$, the co-ordinates of the third vertex are

• A. $(0,a)$
• B. $(\sqrt{3a}/2,-a/2)$
• C. $(0,-a)$
• D. $(-\sqrt{3a}/2,a/2)$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $(0,a)$
B $(\sqrt{3a}/2,-a/2)$
C $(0,-a)$
D $(-\sqrt{3a}/2,a/2)$