If only the thrust acting on an object is doubled, the pressure on the surface:

Reduces by half

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Triples

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Doubles

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Remains the same

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Solution

The correct option is C Doubles
Pressure is defined as the thrust acting on a body per unit area:
$Pressure = \frac{Thrust}{Area}$

Hence, if the thrust acting on an object is doubled (keeping the area constant), the pressure acting on the surface would also be doubled.

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