If →A=2^i−3^j+5^k, →B=−3^i+5^k and →C=−3^i−2^j, then →A−2→B+3→C is
A
−^i−9^j−5^k
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B
^i−9^j−5^k
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C
−^i+9^j−5^k
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D
−^i−9^j+5^k
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Solution
The correct option is A−^i−9^j−5^k Given, →A=2^i−3^j+5^k, →B=−3^i+5^k and →C=−3^i−2^j So, →A−2→B+3→C=(2^i−3^j+5^k)−2(−3^i+5^k)+3(−3^i−2^j) ⇒(−^i−9^j−5^k)