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Question

If a=2^i+4^j+3^k,b=^i+2^j+^k, then the scalar product and the angle between them are

A
13, cos113174
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B
20, cos120184
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C
9, cos113174
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D
13, cos129174
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Solution

The correct option is A 13, cos113174
a.b=axbx+ayby+azbz
a=2^i+4^j+3^k,b=^i+2^j+^k
a.b=2+8+3a.b=13

Angle between them is given as
cosθ=a.b|a||b|=13296
θ=cos113174



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