If A - 6 - -15 - and B - -3 - -11 - the magnitude and direction of A - B is

A = 6 î 15 ĵ B = 3 î + 11 ĵ nbsp; A + B =(6 3) î+( 15+11)ĵ =3 î 4ĵ nbsp; |A + B| = √(3^2 +( 4)^2) = 5 θ = tan^ 1 43≈ 53^∘ Hence the correct option is (b). ...

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Byju's Answer

Standard XIII

Physics

Vector Addition

If A = 6 î -1...

Question

If $\to A = 6^i - 15^j$ and $\to B = - 3^i + 11^j$ , the magnitude and direction of $\to A + \to B$ is

5, 53^{\circ}

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5, - 53^{\circ}

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4, 37^{\circ}

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4, - 37^{\circ}

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Solution

The correct option is B $5, - 53^{\circ}$
$\to A = 6^i - 15^j$
$\to B = - 3^i + 11^j$
$\to A + \to B = (6 - 3)^i + (- 15 + 11)^j = 3^i - 4^j$ $| \to A + \to B | = \sqrt{3^{2} + (- 4)^{2}} = 5 θ = {tan}^{- 1} \frac{- 4}{3} \approx - 53^{\circ}$
Hence the correct option is (b).

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If →A=6^i−15^j and →B=−3^i+11^j, the magnitude and direction of →A+→B is

The correct option is B 5,−53∘→A=6^i−15^j →B=−3^i+11^j →A+→B=(6−3)^i+(−15+11)^j=3^i−4^j |→A+→B|=√32+(−4)2=5θ=tan−1−43≈−53∘ Hence the correct option is (b).

If $\to A = 6^i - 15^j$ and $\to B = - 3^i + 11^j$ , the magnitude and direction of $\to A + \to B$ is

The correct option is B $5, - 53^{\circ}$
$\to A = 6^i - 15^j$
$\to B = - 3^i + 11^j$
$\to A + \to B = (6 - 3)^i + (- 15 + 11)^j = 3^i - 4^j$ $| \to A + \to B | = \sqrt{3^{2} + (- 4)^{2}} = 5 θ = {tan}^{- 1} \frac{- 4}{3} \approx - 53^{\circ}$
Hence the correct option is (b).