If A- -4- -3- and B- -6- -8- then magnitude and direction A- -B- will be

The correct option is B 5√( 5 ) ,tan ^ 1 ( 1/2 ) A⃗ + B⃗ =4î #160; 3ĵ + 6î + 8ĵ= 10î + 5ĵ |A⃗ + B⃗ | = √((10)^2 + (5)^2) = 5√(5) tanθ = ...

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Byju's Answer

Standard XII

Physics

Addition and Subtraction in Unit Vector Notation

If A⃗ =4î -...

Question

If $\to A = 4^i - 3^j$ and $\to B = 6^i + 8^j$ then magnitude and direction $\to A + \to B$ will be

5, tan^{- 1} (3 / 4)

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5 \sqrt{5}, tan^{- 1} (1 / 2)

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10, tan^{- 1} (5)

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25, tan^{- 1} (3 / 4)

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Solution

The correct option is B $5 \sqrt{5}, tan^{- 1} (1 / 2)$
$\to A + \to B = 4^i - 3^j + 6^i + 8^j = 10^i + 5^j$

$| \to A + \to B | = \sqrt{(10)^{2} + (5)^{2}} = 5 \sqrt{5}$

$tan θ = \frac{5}{10} = \frac{1}{2} \Rightarrow θ = {tan}^{- 1} (\frac{1}{2})$

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If →A=4^i−3^j and →B=6^i+8^j then magnitude and direction →A+→B will be

The correct option is B 5√5,tan−1(1/2)→A+→B=4^i−3^j+6^i+8^j=10^i+5^j|→A+→B|=√(10)2+(5)2=5√5tanθ=510=12⇒θ=tan−1(12)

If $\to A = 4^i - 3^j$ and $\to B = 6^i + 8^j$ then magnitude and direction $\to A + \to B$ will be

The correct option is B $5 \sqrt{5}, tan^{- 1} (1 / 2)$
$\to A + \to B = 4^i - 3^j + 6^i + 8^j = 10^i + 5^j$

$| \to A + \to B | = \sqrt{(10)^{2} + (5)^{2}} = 5 \sqrt{5}$

$tan θ = \frac{5}{10} = \frac{1}{2} \Rightarrow θ = {tan}^{- 1} (\frac{1}{2})$