If a-b-c are the unit vectors then -a-b-2-b-c-2-c-a-2 does not exceed

The correct option is B 9 Given expression =2(1+1+1) 2∑(a.b) nbsp; =6 2∑(a.b) ....... (i) But (a+b+c)≥ 0 ∴(1+1+1)+2∑a.b≥ 0 ∴ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dot Product of Two Vectors

If a,b,c ar...

Question

If $\to a, \to b, \to c$ are the unit vectors then ${∣ ∣ ∣ \to a - \to b ∣ ∣ ∣}^{2} + {∣ ∣ ∣ \to b - \to c ∣ ∣ ∣}^{2} + {∣ ∣ \to c - \to a ∣ ∣}^{2}$ does not exceed

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a, b

c

{| a - b |}^{2} + {| b - c |}^{2} + {| c - a |}^{2}

¯ ¯ ¯ a . ¯ ¯ b, ¯ ¯ c

| ¯ ¯ ¯ a - ¯ ¯ b |^{2} + | ¯ ¯ b - ¯ ¯ c |^{2} + | ¯ ¯ c - ¯ ¯ ¯ a |^{2}

\to a, \to b

\to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}

\to a, \to b, \to c

| \to a - 2 \to b |^{2} + | \to b - 2 \to c |^{2} + | \to c - 2 \to a |^{2}

\to a \to b

\to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}

Join BYJU'S Learning Program