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Question

If a,b,c are three non coplanar vectors and a vector α is such that α=p(b×c)+q(c×a)+r(a×b) and α(a+b+c)=1 , then [a b c] is equal to

A
p+q+r
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B
1p+q+r
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C
2(p+q+r)
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D
2p+q+r
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Solution

The correct option is B 1p+q+r
Given: α=p(b×c)+q(c×a)+r(a×b) and
α(a+b+c)=1
Now,
αa=p[a b c]
αb=q[a b c]
αc=r[a b c]
Adding them, we have:
α(a+b+c)=(p+q+r)[a b c]
1=(p+q+r)[a b c] [a b c]=1p+q+r

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