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Question

If a=4i+3j+k and b=i2k, then find 2b×a .

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Solution

a=4^i+3^i+^k
b=^i2^k
2b=2^i4^k
|2b×a|=∣ ∣xyz204431∣ ∣
=x(12)y(2+6)+z(6)
or =12^i18^i+6^k

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