Question

If $p=2\frac{1}{3},q=1\frac{5}{7},r=\frac{3}{4}ands=\frac{5}{14}$, then $p(q-r)÷s$= ___.

• A. $4\frac{2}{10}$
  
• B. $6\frac{3}{10}$
• C. $3\frac{5}{11}$
• D. $4\frac{5}{11}$

Answer 1

The correct option is B $6\frac{3}{10}$

Given that,
$p=2\frac{1}{3},q=1\frac{5}{7},r=\frac{3}{4}ands=\frac{5}{14}$
i.e., $p=\frac{7}{3},q=\frac{12}{4},r=\frac{3}{4},d=\frac{5}{14}$

$p(q-r)÷s=\frac{7}{3}(\frac{12}{7}-\frac{3}{4})÷\frac{5}{14}$
$=\frac{7}{3}\left(\frac{48-21}{28}\right)\times \frac{14}{5}$
$=\frac{7}{3}\left(\frac{27}{28}\right)\times \frac{14}{5}$
$=7\times \frac{9}{2}\times \frac{1}{5}$
$=\frac{63}{10}$
$=6\frac{3}{10}$