In a rhombus PQRS, if PQ = 3x − 7 and QR = x + 3, find PS.

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Solution

In rhombus ABCD:

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In square PQRS if $P Q = 3 x - 7$ and $Q R = x + 3$ , Find PS

$In square PQRS : (i) i f P Q = 3 x - 7 a n d Q R = x + 3; f i n d P S (i i) i f P R = 5 x a n d Q R = 9 x - 8. F i n d Q S$

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