Question

In square PORS:

$\text{If}PQ=3x–7\text{and}QR=x+3;\text{find PS}$

Answer 1

Sides of square are equal.


$PQ=QR$
$3x-7=x+3$
$3x-x=3+7$
$2x=10$
$x=5$
$PS=RQ=x+3=5+3=8$